Question:
At present, in self -study Netty, the use of data transmission carrier bytebuf is just learned, and the value obtained by the get method is not understood.

first enter the 1, 2, 3, 4 of Byte type, then enter the INT type 12, and finally enter the BYTE type 5 and 6.

Output buffer.getByte (3) = 4, this is easy to understand, I am aggressive next.

output buffer.getshort (3) = 1024, why?

output buffer.getint (3) = 67108864, why?

Solution:
Generally known:

byte: 1 byte, 8 digits, there are symbols
Short: 2 bytes, 16 bits, symbols
int: 4 bytes, 32 -bit, symbols
Long: 8 bytes, 64 bits, symbols
 

So:

index                                       getshort(index)          index

0—-1： 0000 0001

1 —- 2: 0000 0010 256+2 (0 and 1) 0

2 —- 3: 0000 0011 512+2+1 (1 and 2) 1

3 —– 4: 0000 0100 512+256+4 (2 and 3) 2

4 —- 12: 0000 0000 1024 (3 and 4) 3
5—-       0000 0000
6—-       0000 0000
7—-       0000 1100

8—-5： 0000 0101

9—-6： 0000 0110
 

Short is 2 bytes, 16 -bit, Getshort (0) reads the combination of 0 and 1 bytes, so it is worth 258;

Getshort (1) Read the combination of 1 and 2 bytes, so the value is 515; (actually not 2 and 3, aggressive)

Getshort (2) Read the combination of 2 and 3 bytes, so the value is 772;

Getshort (3) Read the combination of 3 and 4 bytes, so the value is 1024;

Getint () Get the same value ~
 

Getshort (0) The combination of 0 and 1 bytes read 0000000100000010 is converted to decimal equivalent to 258

Getshort (1) The combination of 1 and 2 bytes read 0000001000000011 is converted to decimal equal to 515